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![SOLVED:Use the substitution u=\sqrt{2} \cot x and the identity 1+\cot ^{2} x=\csc ^{2} x to evaluate \int \frac{d x}{1+\cos ^{2} x} . (Hint: Multiply the top and bottom of the integrand by \](https://cdn.numerade.com/ask_previews/7905e301-ab34-453d-a1a1-e950ff8f2741.gif "SOLVED:Use the substitution u=\sqrt{2} \cot x and the identity 1+\cot ^{2} x=\csc ^{2} x to evaluate \int \frac{d x}{1+\cos ^{2} x} . (Hint: Multiply the top and bottom of the integrand by \")
SOLVED:Use the substitution u=\sqrt{2} \cot x and the identity 1+\cot ^{2} x=\csc ^{2} x to evaluate \int \frac{d x}{1+\cos ^{2} x} . (Hint: Multiply the top and bottom of the integrand by \
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SOLVED: ~2 CEZ Venly the Identily. (tan(x) cot())2 ecz(x) csc2(x) Expand the product, and use the Reciprocal and Pythagorean Identities simpllfy. (tan(x) cot(x))2 tan-(x) tan(x) cot(x) tan?(x) (tan?(x) + 1) + (cot?()
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